Question #8e325

1 Answer
Cem Sentin
Mar 1, 2018

#x_1=8#, #x_2=sqrt2-1# and #x_3=-sqrt2-1#

Explanation:

#x^3-6x^2-17x+8=0#

#x^3-8x^2+2x^2-16x-x+8=0#

#x^2*(x-8)+2x*(x-8)-1*(x-8)=0#

#(x-8)*(x^2+2x-1)=0#

From first multiplier, #x_1=8#. From second one, #x_2=sqrt2-1# and #x_3=-sqrt2-1#

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