Question #7bd2c

1 Answer
Abhishek K.
Feb 24, 2018

Option (A) is accepted here.

Explanation:

Given that,

#rarrsintheta+costheta=sqrt(2)cosalpha#

#rarrcostheta*(1/sqrt(2))+sintheta*(1/sqrt(2))=cosalpha#

#rarrcostheta*cos(pi/4)+sintheta*sin(pi/4)=cosalpha#

#rarrcos(theta-pi/4)=cos(2npi+-alpha)#

#rarrtheta=2npi+-alpha+pi/4#

Related questions
Impact of this question
252 views around the world
You can reuse this answer
Creative Commons License