Question

Question #bd1e2

Answer 1

`x = pi/3 , (2pi)/3`

Explanation:

`2sinx-sqrt(3)=0`

`sinx=sqrt(3)/2`

`x=arcsin(sinx)=arcsin(sqrt(3)/2)=> x = pi/3 , (2pi)/3`

For:

`0<=x<=2pi`