How many sodium atoms constitute a #135*g# mass of sodium?

1 Answer
anor277
Nov 4, 2017

It is a fact that #22.99*g# of sodium atoms contains #"Avogadro's number of sodium atoms...."#

Explanation:

And #"Avogadro's number"-=6.022xx10^23*mol^-1#; and so we take the quotient of the masses and multiply this by #"Avogadro's number"#:

#(135*g)/(22.99*g*cancel(mol^-1))xx6.022xx10^23*cancel(mol^-1)~=36xx10^23# #"sodium atoms"#...and note that this value is dimensionless as is required for a number.

From where did we get the molar mass of sodium?

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