# Question #f382a

Newton’s law of universal gravitation is $F = - G . \frac{{m}_{1.} {m}_{2}}{r} ^ 2$ where G is the gravitational constant and the minus sign just shows the force vector points in the opposite direction to the radius vector.
I get 14.66N, taking the mass of the Earth as $6 \times {10}^{24}$ kg and G as $6.67 \times {10}^{-} 11 N {m}^{2} k {g}^{-} 2$