Long divide #x^5+7# by #x^3-1# and find quotient and remainder and express it as fraction?

1 Answer
Nov 8, 2017

#(x^5+7)/(x^3-1)=color(magenta)(x^2)+color(blue)(x^2+7)/(x^3-1)#

Explanation:

We use long division method
#color(white)(XXXXXXX)x^2color(white)(XXXXXX)#
#" "x^3-1)bar(x^5color(white)(XXXXXX)+7)#
#color(magenta)(x^2)(x^3-1) ->""ul(x^5-x^2) larr" Subtract"#
#" "0 +x^2color(white)(XXXX)+7#

As the degree of #x^2+7# is less than that of #x^3-1#, we cannot divide further and

Hence, quotient is #x^2# and remainder is #x^2+7# and

#(x^5+7)/(x^3-1)=color(magenta)(x^2)+color(blue)(x^2+7)/(x^3-1)#