# Question #5ce3f

Balanced: $B a {\left(N {O}_{3}\right)}_{2} \left(a q\right) + N {a}_{2} {C}_{2} {O}_{4} \left(a q\right) \to 2 N a N {O}_{3} \left(a q\right) + B a {C}_{2} {O}_{4}$(s)

Net Ionic: $B {a}^{2 +} \left(a q\right) + {C}_{2} {O}_{4}^{2 -} \left(a q\right) \to B a {C}_{2} {O}_{4}$(s)

#### Explanation:

This is an example of a double replacement reaction

Barium oxalate has a solubilit of 0.929 mg/L
https://en.wikipedia.org/wiki/Barium_oxalate

Sodium nitrate has a solubility of 91.2g/100mL at ${25}^{0}$C.
https://en.wikipedia.org/wiki/Sodium_nitrate

Looking up solubility data allows you to figure out which product is not soluble in water. Every chem student should memorize that nitrate compounds are always soluble in water.

This video covers the topic of how you can predict products of reactions if you are only told what the reactants are.

This video provides an explanation of the process of writing a net ionic equation.

Hope this helps