Question #0602a

1 Answer
Nov 8, 2017

vertical asymptote at #x=2#
horizontal asymptote at #y=1#
y-intercept at #(0,0)#

Explanation:

Let #y=x/(x-2)#
Since you cannot divide by zero, we have a vertical asymptote where the denominator would be zero.

asymptote where #x-2=0#
vertical asymptote at #x=2#

As #x-> oo, y-> x/x=1 :.# horizontal asymptote at #y=1#

For the y intercept, let #y=0#

#0=x/(x-2)#

Since zero divided by anything is zero, y-intercept is when #x=0#
#=(0,0)#

I've never come across the concept of "holes" for graphs though... sorry