Question #10661

1 Answer
Nov 9, 2017

The value of #x# is #x= (2e^3)/(e^3 - 1)#

Explanation:

Yes you are correct about the first step. Now recall that #ln# and #e# are inverses.

#e^(ln(x/(x- 2))) = e^3#

#x/(x - 2) = e^3#

#1/e^3 = (x- 2)/x#

#1/e^3 = x/x - 2/x#

#2/x = 1 - 1/e^3#

#x = 2/((e^3 - 1)/e^3)#

#x= (2e^3)/(e^3 - 1)#

Hopefully this helps!