What does the graph of #f(x) = (sin^3x + sinxcos^2x)/sinx# look like?

1 Answer
Nov 9, 2017

We start by noticing that for it to be defined, the function cannot have #sinx = 0#, aka #x != 2pin# or #pi + 2pin#. Now we notice

#f(x) = (sinx(sin^2x+ cos^2x))/sinx#

#f(x) = sin^2x + cos^2x#

#f(x) = 1#

So the graph of the function will be the line #y = 1#, but with holes at #x = 2pin# or #x = pi + 2pin#, where #n# is an integer.

Hopefully this helps!