Given #f(t) = (t^2-1)/t#: What are the stationary points of #f(t)# on the real co-ordinate plane, if any?
1 Answer
Nov 11, 2017
No stationary points on the real co-ordinate plane.
Explanation:
Apply quotient rule
For stationary points
Thus, where:
No real values of
Hence,
We can deduce this result from the graph of
graph{(x^2-1)/x [-7.023, 7.024, -3.51, 3.513]}