Question #0636e

1 Answer
Nov 11, 2017

#{y in RR | 9 <= y < oo}#

Explanation:

#f(x)=(x-2)^2+9#

There are no restrictions on #x# so domain of #f(x)# is:

#{x in RR }#

Minimum value of #f(x)#

#y= ((2)-2)^2+9=(0)^2+9=9#

as #x-> +-oo# , #color(white)(88)(x-2)^2+9-> oo#

(#( x-2)^2#is always positive or zero )

So range is:

#{y in RR | 9 <= y < oo}#

Graph:

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