Question #2af0c

1 Answer
Nov 16, 2017

#CI_(95%)" "(134.88,155.12)#

Explanation:

for a confidence interval we calculate

#barx+-zsigma/sqrtn#

we are not told the distribution but since#" "n>30# we can use the Central Limit theorem which states that the distribution of the sample means will be approximately Normal

for a #95% CI#

#z=1.96#

we have

#145+-1.96xx40/sqrt60#

#=145+-10.12(2dp)#

#CI_(95%)" "(134.88,155.12)#