Question #d42b1

1 Answer
Nov 12, 2017

#x=-6,x=4#

Explanation:

#"to calculate the zeros set "f(x)=0#

#rArrx^2+2x-24=0#

#"the factors of - 24 which sum to + 2 are + 6 and - 4"#

#rArr(x+6)(x-4)=0#

#"equate each factor to zero and solve for x"#

#x+6=0rArrx=-6#

#x-4=0rArrx=4#

#"the zeros are "x=-6,x=4#
graph{(y-x^2-2x+24)((x+6)^2+y^2-0.05)((x-4)^2+y^2-0.05)=0 [-10, 10, -5, 5]}