How do you graph a circle a circle with a center at #(0, -6)# and a radius of 1?
1 Answer
Nov 12, 2017
See a solution process below:
Explanation:
The equation for a circle is:
Where
We can rewrite the equation in the problem as:
So, the center of the circle will be at:
graph{(x^2 + (y+6)^2 - 1)(x^2 + (y+6)^2 - 0.0025) = 0 [-5, 5, -8, -3]}