Question #39c61

1 Answer
CW
Feb 15, 2018

Let #angleA=x#,
#=> angleB=4x#,
#=> angleC=5x-13#
As #angleA+angleB+angleC=180^@#,
#=> x+4x+(5x-13)=180#
#=> 10x=180+13=193#,
#=> x=193/10=19.3^@#

Hence,
#angleA=x=19.3^@#,
#angleB=4x=4xx19.3=77.2^@#
#angleC=5x-13=(5xx19.3)-13=83.5^@#

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