Question #a1c35

1 Answer
Nov 26, 2017

#(x+4)^2+(y-5/2)^2=16#

Explanation:

#"the equation of a circle in standard form is "#

#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#

#"where "(a,b)" are the coordinates of the centre and "#
#"r is the radius"#

#"the circle is a tangent to the y-axis"#

#rArr"r is the distance from the centre to the y-axis"#

#(-4,5/2)to(0,5/2)rArrr=0-(-4)=4#

#rArr(x+4)^2+(y-5/2)^2=16larrcolor(blue)"equation of circle"#
graph{((x+4)^2+(y-5/2)^2-16)((x+4)^2+(y-5/2)^2-0.04)=0 [-10, 10, -5, 5]}