Question #ae625

1 Answer
iceman
Nov 15, 2017

No real roots, complex roots.

Explanation:

#ax^2+bx+c=0# => quadratic equation in standard form, to analyze the roots of the equation without solving it we use the
Discriminant:
#D=b^2-4ac# => so in this case:
#7m^2-7m+9=0# => a = 7, b = -7 , c = 9:
#D=(-7)^2-4*7*9#
#D= 49-252#
#D=-203<0#
the discriminant is negative, there are no real solutions, the roots are not real they are complex.

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