A #120g# mass of sodium hydroxide is dissolved in water to give #2.50L# of solution. What is the molarity of the solution?

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Answer 1 · 2017-11-19T03:26:22

#[NaOH]>=1.0*mol*L^-1#

We take the quotient....#"Moles of solute"/"Volume of solution"#.

And we ASSUME here #"Volume of solution"-=2.5*L#...

And so #[NaOH]=((120.0*g)/(40.0*g*mol^-1))/(2.5*L)=??*mol*L^-1#.....

A #120*g# mass of sodium hydroxide is dissolved in water to give #2.50*L# of solution. What is the molarity of the solution?