Question

A block of dry ice sublimes to give a `3700*L` volume of carbon dioxide at `"STP"`. What is the mass of carbon dioxide BEFORE the sublimation?

Answer 1

Well `"STP"` specifies a temperature of `273.15* K`, and an absolute pressure of exactly `10^5 Pa`, `"(100 kPa, 1 bar)"`.

Explanation:

We solve for `n` `"the number of moles"` in the Ideal Gas Equation....

`n=(PV)/(RT)=(1*"bar"xx3700*L)/(8.31451xx10^-2*(L*"bar")/(K*mol)xx273.15*K)`

`=162.9*1/(1/(mol))=162.9*mol`

And of course we had a mass of `162.9*molxx44.01*g~=7*kg` BOTH BEFORE AND AFTER THE DRY ICE CHUNK SUBLIMED....