# Question #43c20

Jan 14, 2018

$40.28 m$

#### Explanation:

Upward component of velocity of the arrow is $49 \sin 35$ = $u$

Now,if it reaches a maximum height of $h$ we can write the values in the equation,

$\left({V}^{2}\right) = \left({u}^{2}\right) - 2 g h$
Where $V = 0$
So,$h = 40.28 m e t e r s$