How do you find the intercepts and graph #x+y=6# ?

2 Answers
Dec 12, 2017

Answer:

Find intercepts and draw a line through them...

Explanation:

Given:

#x+y=6#

Note that if you set #x=0# (or equivalently cover up the #x# term), then the resulting equation is:

#y=6#

Similarly, if you set #y=0# (or equivalently cover up the #y# term), then the resulting equation is:

#x=6#

So the intercepts of this line with the #y# and #x# axes are #(0, 6)# and #(6, 0)# respectively.

We can now draw the graph by drawing a straight line through these two intercepts...

graph{(x+y-6)((x-6)^2+y^2-0.02)(x^2+(y-6)^2-0.02)=0 [-7.75, 12.25, -1.56, 8.44]}

Dec 12, 2017

Answer:

#"see explanation"#

Explanation:

#"one way is to find the intercepts that is where the "#
#"graph crosses the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0to0+y=6rArry=6larrcolor(red)"y-intercept"#

#y=0tox+0=6rArrx=6larrcolor(red)"x-intercept"#

#"plot "(0,6)" and "(6,0)" and draw a straight line"#
#"through them"#
graph{-x+6 [-20, 20, -10, 10]}