Question #02789

Question

243 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-01T17:08:54

#y=...,-13(pi)/6,-7(pi)/6,-pi/6,5pi/6,11pi/6,...#

Given:

#y=cot^-1(-sqrt3)#

#coty=-sqrt3#

cot is negative in second and fourth quadrants

#cot(pi/6)=sqrt3#

#..-2pi-(pi)/6,-pi-pi/6,-(pi)/6,pi-(pi)/6, 2pi-(pi)/6, , ...#
y can take values as

#y=...,-13(pi)/6,-7(pi)/6,-pi/6,5pi/6,11pi/6,...#