# Question #5fb9b

Nov 24, 2017

$N a O H \left(a q\right) + C {O}_{2} \to N a H C {O}_{3} \left(a q\right)$

#### Explanation:

This is a two stage reaction.

The carbon dioxide first reacts with water to form the intermediate, carbonic acid:

$C {O}_{2} + {H}_{2} O \left(l\right) \to {H}_{2} C {O}_{3} \left(a q\right)$

Then the carbonic acid reacts with sodium hydroxide to form the product, sodium bicarbonate:

${H}_{2} C {O}_{3} \left(a q\right) + N a O H \left(a q\right) \to N a H C {O}_{3} \left(a q\right) + {H}_{2} O \left(l\right)$

We can combine these equations to get an overall summary of the reaction:

$C {O}_{2} + {H}_{2} O \left(l\right) + {H}_{2} C {O}_{3} \left(a q\right) + N a O H \left(a q\right) \to N a H C {O}_{3} \left(a q\right) + {H}_{2} O \left(l\right) + {H}_{2} C {O}_{3} \left(a q\right)$

This isn't very easy to read, so we cancel out ${H}_{2} O$ and ${H}_{2} C {O}_{3}$ from both sides (just like you would do with a mathematical equation), and we are left with our summary equation:

$N a O H \left(a q\right) + C {O}_{2} \to N a H C {O}_{3} \left(a q\right)$