Question #ea7e8

1 Answer
Nov 22, 2017

We have vectors #bb(ul a)# and #bb(ul b)# such that:

# (bb(ul a) * bb(ul b))^2 = | bb(ul a) |^2 \ | bb(ul b) |^2 #

Using the definition of the dot (or scalar) product, and denoting the angle between # bb(ul a)# and #bb(ul b)# by #theta#, we have:

# (| bb(ul a) | \ | bb(ul b) | \ cos theta)^2 = | bb(ul a) |^2 \ |bb(ul b)|^2 #

And so:

# | bb(ul a) |^2 \ |bb(ul b)|^2 - | bb(ul a) |^2 \ | bb(ul b) |^2 \ cos^2theta = 0#
# :. | bb(ul a) |^2 \ |bb(ul b) |^2 \ ( 1 - cos theta )= 0#

Leading to:

A) Either: # | bb(ul a) |^2 \ |bb(ul b) |^2 => | bb(ul a) | = 0# or #| bb(ul b) | = 0#

# => bb(ul a) = 0# or # bb(ul b) = 0#

But we are given that # bb(ul a) # and # bb(ul b) # are non-zero, eliminating this as as possible solution.

B) Or: #cos theta-1=0=> cos theta =1#

# => theta =0 #
# => bb(ul a)# and # bb(ul b) # are parallel QED.