Question

How many moles of oxygen gas express a volume of `1*m^3` at `293.15*K` and a pressure of `1*atm`? And what is the mass of dioxygen?

Answer 1

Well, we could solve the ideal gas equation.....

Explanation:

We note first that `1*m^3-=1000*L`, i.e. a cubic meter is a LARGE volume, and then we solve the ideal gas equation..

`n=(PV)/(RT)=(1*atmxx1000*L)/(0.0821*(L*atm)/(K*mol)xx293.15*K)=41.6*mol`

And this represents a mass of `41.6*molxx32.00*g*mol^-1~=1.3*kg`