Question #4d2b7

2 Answers
Nov 23, 2017

C)

Explanation:

"Brute Force" method just sets the expressions equal and checks the values. There may be a more refined trig way to manipulate the expressions, but this is simplest for multiple-choice.
#12sin^2x = 1 - sinx#

#sin^2x = (1 - sinx)/12# (easier to calc/compare from the sine vales)

#x = 194.5# or #344.5#
#sinx = -0.25# ; #sin^2x = 0.06#

#0.063 = 0.75/12 = 0.63#

Nov 23, 2017

#(B)#

Explanation:

#12sin2x+sinx-1=0#

#sin2x=2sinxcosx#

#24sinxcosx+sinx-1=0#

#cosx=(1-sinx)/(24sinx)#

#cos^2x=(1-sinx)^2/(576sin^2x)#

#1-sin^2x=(1+sin^2x-2sinx)/(576sin^2x)#

#576sin^2x(1-sin^2x)=1+sin^2x-2sinx#

#576sin^2x-576sin^4x-1-sin^2x+2sinx=0#

#-576sin^4x+575sin^2x+2sinx-1=0#

Now you would have to solve for #sinx# which is not easy from this equation of 4th degree.

I think you meant:

#12sin^2x+sinx-1=0#

You can use the quadratic formula to solve for #sinx#:

#x=(-b+-sqrt(b^2-4ac))/(2a)#

#sinx=(-1+-sqrt(1^2-4(12)(-1)))/(2(12)#

#sinx=(-1+-7)/24#

One answer is:

#sinx=-1/3#

#x=arcsin(-1/3)=-19.47 Degrees# which is answer #(B)#

The second answer is:

#sinx=1/4#

#x=arcsin(1/4)=14.5 Degrees#

Even though this matches answer #(A)# it is not correct because it does not fall in the given interval.

Answer #(B)# is the only correct answer.