Question #f2551

1 Answer
P dilip_k
Nov 23, 2017

#sin2xcos2x-cos2x+sin2x=1#

#=>sin2xcos2x-cos2x+sin2x-1=0#

#=>cos2x(sin2x-1)+1(sin2x-1)=0#

#=>(sin2x-1)(cos2x+1)=0#

#sin2x=1 and cos2x=-1#

when
#sin2x=1 =sin(pi/2)#

#2x=npi+(-1)^npi/2 " where " nin ZZ#

#=>x=(npi)/2+(-1)^npi/4 " where " nin ZZ#

when
#cos2x=-1 =cospi#

#=>2x=2mpipmpi" where " m in ZZ#

#=>x=mpipmpi/2" where " m in ZZ#

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