Question

What is the molality of a `1.3*g` mass of `HCl` solution in water, that is `85%` `"w/w"` with respect to the solute, and has a volume of `1*mL`?

Answer 1

Well by definition, `"molality"="moles of solute"/"kilograms of solvent."`

Explanation:

And we have the data to perform this calculation.....and we work from a `1*cm^3` volume (whose mass is of course `1.3*g`...)

We gots `((1.3*gxx85%)/(36.46*g*mol^-1))/(1.3*gxx10^-3*kg*g^-1xx15%)`

`=??*mol*kg^-1`...

These data are unreasonable, and the max. concentration you can get for `HCl` is maybe `38%` `"w/w"`...