Question

Question #4141d

Answer 1

`LHS=(1+1/tan^2A)(1+1/cot^2A)`

`=(1+cot^2A)(1+tan^2A)`

`=csc^2Asec^2A`

`=1/(sin^2Acos^2A)`

`=1/(sin^2A(1-sin^2A))`

`= 1/(sin^2A-sin^4A)=RHS`