Question #808c0

1 Answer
Nov 26, 2017

For your first question, I'll have to explain what a log is. A log to a base #a#, i.e. #log_a(x)=b#, is another way of writing #a^x=b# or #a=root(x)(b)#. For example, #log_10(100)# will give us 2 because #sqrt(100)=10#, and #10^2=100#.

#a^(log_a(b))=b#. This can shown with #10^(log_10(100))#, #log_10(100)=2, 10^2=100#.

So, #log_5(4)# will tell you what number 5 has to be raised to the power of to get 4, in this case, 5 is raisedbto the power of that number, therefore giving 4.

For #log_3(2x+5)=2#, we know that the value for #x# will have to give us a number which when put into #2x+5# equals #3^2=9#

#9=2x+5#

#2x=4#

#x=4/2=2#