Question

Question #9158c

Answer 1

`x=kpi,+-1/3pi+2kpi, k in ZZ`

Explanation:

`sin2x-sinx=0`

Use `sin2x=2sinxcosx`

`2sinxcosx-sinx=0`

`sinx(2cosx-1)=0`

`sinx=0rArrx=kpi, k in ZZ`

`2cosx-1=0`

`cosx=1/2rArrx=+-1/3pi+2kpi, k in ZZ`