Question #ad61b

1 Answer
Nov 27, 2017

#x = (5pi)/12 + pin and pi/12 + pin#

Explanation:

We can rewrite as:

#2(2sinxcosx) = 1#

#2sinxcosx = 1/2#

We know that #sin(2x) = 2sinxcosx#.

#sin(2x) = 1/2#

#2x= arcsin(1/2) + 2pin#

#2x = (5pi)/6 + 2pin and pi/6 + 2pin#

#x = (5pi)/12 + pin and pi/12 + pin#

Where #n# is an integer.

Hopefully this helps!