Question

Question #c5f03

Answer 1

I tried this:

Explanation:

Consider the diagram for a general rectangle:

we have:
`2a+b=30`
and so:
`b=30-2a`
into the area:
`axx(30-2a)=100`
so that:
`2a^2-30a+100=0`
solve for `a` (quadratic equation):
`a_1=10m`
`a_2=5m`
so that:
`b_1=10m`
or
`b_2=20m`