Question

Question #bd889

Answer 1

The graph would look like this

Explanation:

Compare `y=-1/4log_2(1/2x)+1` with `y-k=clog_2 d(x-h)`
Then, use this general transformation:
(x,y) corresponds to `(x/d+h,cy+k)`
The point (x,y) on `y=log_2x` corresponds to the point `(2x,-1/4y+1)` on `y=-1/4log_2(1/2x)+1`

If it helps, you could also always use a table to plot, but you may miss key points.