Question #2e462

1 Answer
P dilip_k
Nov 28, 2017

Given #11A=90#

#=>10A+A=90#

#=>tan(10A+A)=tan90#

#=>(tan10A+tanA)/(1-tanAtan10A)=tan90#

#=>(1-tanAtan10A)/(tanA+tan10A)=1/tan90=0#

#=>1-tanAtan10A=0#

#=>tanAtan10A=1#

Similarly

#tan2Atan9A=1#

#tan3Atan8A=1#

#tan4Atan7A=1#

#tan5Atan6A=1#

So multiplying those equations we get

#tanAtan2Atan3A.....tan10A=1#

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