Question #3ddba

1 Answer
Abhishek K.
Nov 29, 2017

See below.

Explanation:

By cross multiplication, we have
#tan^2x-sin^2x=sin^2x*tan^2x#

#New LHS=tan^2x-sin^2x#

#=sin^2x/cos^2x-sin^2x#

#=sin^2x(1/cos^2x-1)#

#=sin^2x((1-cos^2x)/cos^2x)#

#=sin^2x/cos^2x(1-cos^2x)#

#=tan^2x*sin^2x=New RHS#

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