Question #3ad56

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Answer 1 · 2017-11-28T23:26:43

#2/5#

You find a number that you can divide the denominator and numerator by and then you divide it by that number until you cant divide it no more.

In the above context we have;

#8/20#

#(4 xx 2)/(4 xx 5)#

#(cancel4 xx 2)/(cancel4 xx 5)#

#(1 xx 2)/(1 xx 5)#

#2/5#

Answer 2 · 2017-12-04T17:48:40

#2/5#

Divide both the numerator and denominator by the HCF.

#8/20#

IN this case:

#(8div4)/(20div4) = 2/5#