How do you simplify #(secx + cscx)^2cotx#?

1 Answer
Nov 29, 2017

#csc^3xsecx(1 + sin2x)#

Explanation:

We have:

#(1/cosx + 1/sinx)^2 * cosx/sinx#

#((sinx + cosx)/(sinxcosx))^2 * cosx/sinx#

#(sin^2x + 2sinxcosx + cos^2x)/(sin^2xcos^2x) * cosx/sinx#

#(1 + 2sinxcosx)/(sin^2xcos^2x) * cosx/sinx#

#(1 + sin2x)/(sin^3xcosx)#

#csc^3xsecx(1 + sin2x)#

Don't know if this simplifies much--hopefully this was the answer you were looking for.