How do you simplify #(secx + cscx)^2cotx#?
1 Answer
Nov 29, 2017
Explanation:
We have:
#(1/cosx + 1/sinx)^2 * cosx/sinx#
#((sinx + cosx)/(sinxcosx))^2 * cosx/sinx#
#(sin^2x + 2sinxcosx + cos^2x)/(sin^2xcos^2x) * cosx/sinx#
#(1 + 2sinxcosx)/(sin^2xcos^2x) * cosx/sinx#
#(1 + sin2x)/(sin^3xcosx)#
#csc^3xsecx(1 + sin2x)#
Don't know if this simplifies much--hopefully this was the answer you were looking for.