Question #62ffc

1 Answer
Nov 29, 2017

#(-15t-10t^2)hatk#

Explanation:

The best way to find the cross product is to find the determinant of the matrix in the following form, expanding about the first row. It is important to remember to us the second row for A and the third row for B when finding product #AxxB# and vice versa, since the vector product in non commutative.

#[(i,j,k),(3t,5,0),(2t^2,-5,0)]#

#hati[(5*0)-(-5*0)]-hatj[(3t*0)-(2t^2*0)]+hatk[(3t*-5)-(2t^2*5)]#

#i[(0)-(0)]-j[(0)-(0)]+k[(-15t)-(10t^2)]#

#(-15t-10t^2)hatk#