Question #8a13f
1 Answer
Nov 29, 2017
Explanation:
The Quotient Rule is
#dy/dx = d/dx (u/v) = (v (du)/dx - u (dv)/dx )/v^2#
Use
#dy/dx = ( (2-x) d/dx (1+x) - [(1+x) d/dx (2-x)] ) / (2-x)^2#
Use the Power Rule to differentiate:
#dy/dx = ((2-x)(0+1) - [(1+x)(0-1)] ) / (2-x)^2#
# = ( (2-x) - (-1-x) ) / (2-x)^2#
# = ( 2-x + 1 + x ) / (2-x)^2 #
# = 3/(2-x)^2#
Thus,