Question #522f4
1 Answer
Nov 30, 2017
#(g@h)(-4+a)=8-4a#
Explanation:
#"calculate "(g@h)(a)#
#"substitute "h(a)" into "g(a)#
#rArr(g@h)(a)=g(color(red)(-2a-5))#
#color(white)(xxxxxxxx)=2(color(red)(-2a-5))+2#
#color(white)(xxxxxxxx)=-4a-8#
#"to calculate "(g@h)(-4+a)" substitute "(-4+a)" "#
#"into "(g@h)(a)#
#rArr(g@h)(color(magenta)(-4+a))=-4(color(magenta)(-4+a))-8#
#color(white)(xxxxxxxxxxxxxx)=8-4a#
