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Question #f7c68

1 Answer

Dec 1, 2017

#1#

Explanation:

#lim_(xrarr0)cosx = 1# and #lim_(xrarr0)asinbx = 0#, so

#lim_(xrarr0)(cosx+asinbx)^(1/2) = (1+0)^(1/2) = 1#

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