Question #e6e17

1 Answer
Nov 30, 2017

See below.

Explanation:

LHS

#(costheta-sintheta)^2=cos^2theta-2costhetasintheta+sin^2theta#

#->=cos^2theta+sin^2theta-2costhetasintheta#

Identity: #color(red)(sin^2theta+cos^2theta=1)#

#->=1-2costhetasintheta#

#LHS-=RHS#