Given that an electronic transition for the hydrogen atom obeys the formula... #DeltaE=-2.178xx10^-18{1/n_"final"^2-1/n_"initial"^2}*J#. What is #DeltaE# for the ionization of the hydrogen atom?

1 Answer

Well, you got the formula.....

Explanation:

You have also specified that #n_"final"=oo#..

And #1/oo^2=0#

And so....

#DeltaE=-2.178xx10^-18{1/n_"final"^2-1/n_"initial"^2}*J#

#=-2.178xx10^-18{0-1/1^2}*J#

#=2.178xx10^-21*kJ//at om#