Question

Question #c2ac4

Answer 1

The vertex form is `f(x) = (x-9/2)^2-81/4`.

Explanation:

Vertex form is `f(x) = a(x-h)^2+k`

The vertex `(h,k)` of a quadratic `ax^2+bx+c` can be found from `h=-b/(2a)` and `k=f(h)`.

For this quadratic `a=1,b=-9`, and `c=0`. So we know that `h=-(-9)/(2(1))=9/2`.

`k=f(9/2) = (9/2)^2-9(9/2) = 81/4-81/2 = -81/4`.

The vertex form is `f(x) = (x-9/2)^2-81/4`.

Answer 2

f(x)= `(x-9/2)^2` -`81/4`

Explanation:

The vertex is ( h,k )

h can be found by `-b/(2a)`

After finding h you can insert it into the original equation

After doing so you will get -`81/4` as k.

Now that you have the vertex (`9/2`, -`81/4`) pug them into Vertex form: F(x) = `(x-h)^2`+k

This can also be solved by completing the square.