# Question #bccac

##### 2 Answers

By converting the equation in point-slope form to slope-intercept form, we obtain

#### Explanation:

Given the slope of a line and a point on it, we can write its equation in **point-slope form**, denoted by:

Where

Let’s plug those values in:

We can now move around terms to convert this to **slope-intercept form**:

#### Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

#"where m is the slope and b the y-intercept"#

#"here "m=8/9#

#rArry=8/9x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(6,-8)" into the partial equation"#

#-8=(8/9xx6)+brArrb=-8-16/3=-40/3#

#rArry=8/9x-40/3larrcolor(red)"in slope-interceot form"#