# Question #bf7f4

##### 1 Answer

Dec 3, 2017

That is correct. Furthermore, the function increases for

#### Explanation:

A function is increasing if

#frac{dy}{dx} > 0#

#8x - 1/x^2 >0#

Since

#8x^3 - 1 > 0#

#8x^3 > 1#

#x^3 > 1/8#

Since the cube root is an increasing function, taking the cube root on both sides does not change the sign too.

#x > 1/2#

The point