# Question #acd95

Dec 3, 2017

The distance from the edge of the well to the water's surface $= 11.25 m$

#### Explanation:

Using equation of motion: $s = u t + \frac{1}{2} a {t}^{2}$

where $s$ is distance, $t$ is time = $1.5 \sec$
$u$ is initial velocity= $0$ as it starts from rest,
and $a$ is acceleration due to gravity $\approx 10 \frac{m}{s} ^ 2$ .

$s = 0 \times t + \frac{1}{2} a \times {t}^{2}$

$s = \frac{1}{2} \times 10 m {s}^{-} 2 \times {\left(1.5\right)}^{2} {\sec}^{2}$

$s = 11.25 m$