Question

Question #abecf

Answer 1

`(cos((2pi)/3)-isin((2pi)/3))^11`

`=(cos((22pi)/3)-isin((22pi)/3))`

`=cos(7pi+pi/3)-isin(7pi+pi/3)`

`=-cos(pi/3)+isin(pi/3)`

`=-1/3+sqrt3/2i`